1.

An ac generator has a coil of 250 turns rotating at 60 Hz in a magnetic field of 0.6/π T. What must be the area of each turn of the coil to produce a maximum emf of 180 V ?

Answer»

Data : N = 250, 

f = 60 Hz, B = \(\cfrac{0.6}π\)T

e0 = NABω = NAB (2πf)

∴ A = \(\cfrac{e_0}{NB2πf}\) = \(\cfrac{180}{(250)(0.6/π)(2π×60)}\)

\(\cfrac{18}{25 \times 72}\)

= 10-2 m2

This must be the area of each turn of the coil.



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