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An ac generator has a coil of 250 turns rotating at 60 Hz in a magnetic field of 0.6/π T. What must be the area of each turn of the coil to produce a maximum emf of 180 V ? |
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Answer» Data : N = 250, f = 60 Hz, B = \(\cfrac{0.6}π\)T e0 = NABω = NAB (2πf) ∴ A = \(\cfrac{e_0}{NB2πf}\) = \(\cfrac{180}{(250)(0.6/π)(2π×60)}\) = \(\cfrac{18}{25 \times 72}\) = 10-2 m2 This must be the area of each turn of the coil. |
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