An ac generator spinning at a rate of 750 rev/min produces a maximum e

1.	An ac generator spinning at a rate of 750 rev/min produces a maximum emf of 45 V. At what angular speed does this generator produce a maximum emf of 102 V ?
Answer» Data : e₁ = 45 V, f₁ = 750 rpm, e₂ = 102 V e = NABω = NAB(2πf) ∴ e ∝ f ∴ \(\cfrac{e_2}{e_1}\) = \(\cfrac{f_2}{f_1}\) ∴ f₂ = \(\cfrac{e_2}{e_1}\) x f₁ = \(\cfrac{102}{45}\) x 750 = 1700 rpm This is the required frequency of the generator coil.

An ac generator spinning at a rate of 750 rev/min produces a maximum emf of 45 V. At what angular speed does this generator produce a maximum emf of 102 V ?

Answer»

Data : e₁ = 45 V,

f₁ = 750 rpm, e₂ = 102 V

e = NABω = NAB(2πf) ∴ e ∝ f

∴ \(\cfrac{e_2}{e_1}\) = \(\cfrac{f_2}{f_1}\)

∴ f₂ = \(\cfrac{e_2}{e_1}\) x f₁ = \(\cfrac{102}{45}\) x 750 = 1700 rpm

This is the required frequency of the generator coil.

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An ac generator spinning at a rate of 750 rev/min produces a maximum emf of 45 V. At what angular speed does this generator produce a maximum emf of 102 V ?

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