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An AC source is connected with a resistance ( R) and an unchanged capacitance C, in series. The potential difference across the resistor is in phase with the initial potential difference across the capacitor for the first time at the instant (assume that at t =0 , emf is zero)A. `pi/Omega`B. `2pi/Omega`C. `pi/2Omega`D. `3pi/2Omega` |
Answer» Correct Answer - D Let V = `V_o sin Omegat ` [as V = 0 at t = 0] Then `V_R = V_o sin omega`t and `V_C = V_0 sin(omegat - pi / 2)` C and `V_R` are in same phase . While `V_C` lags V (or `V_R) by 90^(@)` . Now `V_R` is in same phase with initial potential difference across the capacitor for the first time when, `omegat = pi / 2 + 2pi = 3pi/ 2` `therefore` `t = 3pi/2omega` |
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