A 200 km telephone wire has capacity of `0.014 muF km^(-1)`. If it carries an alternating current oif frequency 50kHz, what should be the value of an inductance required to be connected in series so that impedance is minimumn ?

A 200 km telephone wire has capacity of `0.014 muF km^(-1)`. If it car

1.	A 200 km telephone wire has capacity of `0.014 muF km^(-1)`. If it carries an alternating current oif frequency 50kHz, what should be the value of an inductance required to be connected in series so that impedance is minimumn ?
Answer» Capacitance , `C = 0.014 xx 200muF = 2.8 xx 10^(-16)F` Frequency, `f = 50 k Hz = 50 xx 10^(3) cycl es s^(-1)` The impedance will be minimum at resonant frequency , when applied frequency will be same as resonant frequency `(f_(0) = f)`. The resonant frequency , `f_(0) = 1/(2pisqrt (LC)) implies L = 1/(4pi^(2) f_(0)^(2) C)` ` L = 1/(4 xx 22/7 xx 22/7 xx (50 xx 10^(3))^(2) xx (2.8 xx 10^(-6))) = 0.36 xx 10^(-5) H`

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A 200 km telephone wire has capacity of `0.014 muF km^(-1)`. If it carries an alternating current oif frequency 50kHz, what should be the value of an inductance required to be connected in series so that impedance is minimumn ?

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