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An acid base indicator has `K_(HIn)=3.0xx10^(-5)`. The acid from of the indicator is red and the basic form is blue the change in `(H^(+))` required to change the indicator from 75% red to 75%blue is :-A. `8xx10^(-5)M`B. `9xx10^(-5)M`C. `10^(-5)M`D. `3xx10^(-4)M` |
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Answer» Correct Answer - A `[H^(+)]=K_(In)xx(["Hin"])/(["In"^(-)])` Case` I [H^(+)]_(1)=3xx10^(-5)xx(0.75)/(0.25)=9xx10^(-5)` Case `II [H^(+)]_(2)=3xx10^(-5)xx(0.25)/(0.75)=1xx10^(-5)` Change in`[H^(+)]=8xx10^(-5)` |
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