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An acid having pH = 6 is diluted 1000 times. What will be the pH of the final solution ? |
Answer» pH = 6 means `[H_(3)O^(+)=10^(-6)M`. After diluting 1000 times, `[H_(3)O^(+)]=10^(-6)//1000M = 10^(-9)M`. `:. [H_(3)O^(+)]` from `H_(2)O` cannot be neglected. Total `[H_(3)O^(+)]=10^(-9)+10^(-7)(10^(-2)+1)=10^(-7)(1.01)` `:. pH = - log (1.01xx10^(-7))=7-0.0043=6.9957`. |
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