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An acid solution of 0.2 " mol of "`KReO_(4)` was reduced with Zn and then titrated with 1.6 " Eq of "acidic `KMnO_(4)` solution for the reoxidation of the ehenium `(Re)` to the perrhenate ion `(ReO_(4)^(ɵ))`. Assuming that rhenium was the only elements reduced, what is the oxidation state to which rhenium was reduced by Zn?A. 1B. 2C. `-1`D. `-2` |
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Answer» Correct Answer - C Eq of `K Re O_(4) -=` Eq of `MnO_(4)^(-)` `0.2 xx n = 1.6` Eq, `n = (1.6)/(0.2) = 8` Hence, ther is an `8e^(-)` reduction. `8e^(-) +overset(+7)(ReO_(4)^(-)) rarr underset(x =- 1)(Re^(-1))` oxidation state of `Re =- 1` |
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