An aeroplane is flying from city A to city B along path 1. The path 1 is a circular arc whose centre coincides with the centreof the earth. Another aeroplane is flying along path 2 from A to B. The path 2 is circular arc whose centre is at C. O is the centre of the earth. Then,

An aeroplane is flying from city A to city B along path 1. The path 1

1.	An aeroplane is flying from city A to city B along path 1. The path 1 is a circular arc whose centre coincides with the centreof the earth. Another aeroplane is flying along path 2 from A to B. The path 2 is circular arc whose centre is at C. O is the centre of the earth. Then,
Answer» The distance travelled by `1^(st)` aeroplane is greater than that of `2^(nd)`aeroplane. The distance travelled by `1^(st)` aeroplane is less than that of `2^(nd)` aeroplane. The displacement of both aeroplane is different. None of these Solution :Let `I_1` = distance travelled by aeroplane 1 along PATH 1 `I_2` = distance travelled by aeroplane 2 along path 2 Let `OC = R/2` Here, for path 1, `2 theta = l_1 /R` But `COSTHETA = R/2R = 1/2 therefore theta = pi/3` `implies 2 xx pi/3 = l_1/R therefore l_1 = 2piR/3 = 0.67 piR` But for path 2 `l_2 = pir = pi("AC") = pi RSIN pi/2 = sqrt 3/2 piR = 0.866 piR` `therefore l_1 lt l_2`