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An air bubble of radius 2 mm is at a depth of 5 cm below the free surface of a liquid of surface tension 0.06 N/m and density 1000 kg/m""^(3). The pressure inside the bubble is greater than the atmospheric pressure by n xx 140 "N/m"^(2). Find the value of n. |
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Answer» Solution :`R=2 MM =2 xx 10^(-3)m` `S=0.007 N//m` `h=5 CM =5 xx 10^(-2)m` `p=1000 kg//m^(3)` `[Pe]=(2S)/(r)+hpg` `=(2 xx 0.07)/(2 xx 10^(-3)) +5 xx 10^(-2) xx 1000 xx 9.8` `=70+490=560N//m^(2)` |
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