1.

An air chamber of volume v has a neck area of cross section a into whicha ball of mass m just fits and can move up and down without any friction. Show that when the ball is pressed down a little and released for the time priod of oscillation, assuming pressure-volume variations of the air to be isothermal.

Answer»

SOLUTION : ,
volume of chamber = V
Area of cross section of neck = a
mass of ball = m
Intially pressure
Let the ball be depressed by y units. Due to depression, there will be reduction in volume and hence, increase of pressure inside chamber.
`therefore` Decrease in volume of chamber = `DELTAV = AY`
`therefore` Volumetric strain` = (DeltaV)/(V) = (ay)/(V)`
`therefore B = Bulk modules= -(P)/((DeltaV)/(V)) = -(PV)/(ay)`
`P = -(Bay)/(V)`
Restoring force `F = PA`
` = -(Ba^(2)y)/(V)`
As `F = -Kx`
`therefore` we can write `K = (Ba^(2))/(V)`
`T = 2pi sqrt((mV)/(Ba^(2)))`


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