1.

An air champer of volume 'V' has a neck area of cross - section A into which a ball of mass m just fits and can move up and down without any friction. Show that when the ball is pressed down a little and released, it executes SHM. Obtain an expression for the time period of oscillation assuming pressure volume variations of air to to be isothermal.

Answer»

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Solution :Let E be the bulk modulus of the material of the BALL. Then,

`E=(-PV)/(DeltaV)`
`"or"P=(-E DeltaV)/(V)" but "F=PA`
`"thereby,"F=(-E DeltaV)/(V)A.` Let .y. be the displacement, Then `DeltaV=Ay.`
`"Hence,"F=-E(A^(2)y)/(V).` However using the Newton.s II Law of MOTION,
`F=ma =m(d^(2)y)/(dt^(2))`
Hence `m(d^(2)y)/(dt^(2))=-(EA^(2)y)/(V)`
`"or"(d^(2)y)/(dt^(2))+((EA^(2))/(mV))y=0`
Comparing this with `(d^(2)y)/(dt^(2))+omega^(2)y=0`, we get,
`omega^(2)=(EA^(2))/(mV)"so that " (4pi^(2))/(T^(2))=(EA^(2))/(mV)`
`or T=((2pi)/(A))SQRT((mV)/(E))`.


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