Saved Bookmarks
| 1. |
An air champer of volume 'V' has a neck area of cross - section A into which a ball of mass m just fits and can move up and down without any friction. Show that when the ball is pressed down a little and released, it executes SHM. Obtain an expression for the time period of oscillation assuming pressure volume variations of air to to be isothermal. |
|
Answer» <P> Solution :Let E be the bulk modulus of the material of the BALL. Then, `E=(-PV)/(DeltaV)` `"or"P=(-E DeltaV)/(V)" but "F=PA` `"thereby,"F=(-E DeltaV)/(V)A.` Let .y. be the displacement, Then `DeltaV=Ay.` `"Hence,"F=-E(A^(2)y)/(V).` However using the Newton.s II Law of MOTION, `F=ma =m(d^(2)y)/(dt^(2))` Hence `m(d^(2)y)/(dt^(2))=-(EA^(2)y)/(V)` `"or"(d^(2)y)/(dt^(2))+((EA^(2))/(mV))y=0` Comparing this with `(d^(2)y)/(dt^(2))+omega^(2)y=0`, we get, `omega^(2)=(EA^(2))/(mV)"so that " (4pi^(2))/(T^(2))=(EA^(2))/(mV)` `or T=((2pi)/(A))SQRT((mV)/(E))`. |
|