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An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15^(@). What is the radius of the loop |
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Answer» Solution :Speedof aircraft`v= 720 km^(-1)` `=(720 xx 1000)/(3600)` `=200 MS^(-1)` Gravitationalaccelerationg= 9.8 `ms^(-2)` Whenit takesturn. TAN `theta= (v^(2))/(rg )` `r = (v^(2))/(g tantheta )` `= ((200)^(2))/(9.8 xx tan 15^(@)) = (4000)/(9.8 xx 0.2679)` ` r =15.24km` |
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