An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15^(@). What is the radius of the loop ?

An aircraft executes a horizontal loop at a speed of 720 km/h with its

1.	An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15^(@). What is the radius of the loop ?
Answer» SOLUTION :If N is the normal force on the wings, `N cos theta = mg "" N sin theta = (MV^(2))/(R )` On SIMPLIFICATION, `Tan theta = (v^(2))/(Rg)` `R=(v^(2))/(g tan theta)=(200xx200)/(10xx tan 15^(@))=15 km`