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An aircraft executes a horizontal loop at a speed of 720 km/h with its wings banked at 15^@.What is the radius of the loop ? |
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Answer» Solution :If N is the normal force on the wings, `N COS theta = mg, N SIN theta = (mv^2)/( R)` which give`R = (v^2)/(G tan theta) = (200 xx 200)/(10 xx tan 15^@) = 15 KM` |
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