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An aircraft executes a horizontal loop of radius 1 km with a steady speed of `900 km h^(-1)`. Compare its centripetal acceleration with the acceleration due to gravity. |
Answer» Here `r=1km = 10^(3)m, v=900kmh^(-1)= 900 xx 5/18= 250ms^(-1)` Centripetal acceleration = `a_(c) = v^(2)/r=(250)^(2)/(10^(3)) = 62.5 ms^(-2)` Now, `a_(c)/g=62.5/9.8 = 6.38` |
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