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An aircraft executes a horizontal loop with a speed of 150 m/s with its wings banked at an angle of 12° The radius of the loop is (g = 10 m/s2)(A) 10.6 km (B) 9.6 km (C) 7.4 km (D) 5.8 km |
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Answer» Answer is (A) 10.6 km Using, tan θ = \(\frac{v^2}{rg}\) ∴ tan 12° = \(\frac{(150)^2}{r\times10}\) ∴ r = 10.6 x 103m = 10.6 km |
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