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An aircraft is flying at a height of 3400mabove the ground . If the angle subtended at a ground observation point by the aircreaft positions 10.0 s apart is 30^(@) , what is the speed of the aircraft ? |
Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MOD_UNT_PHY_XI_P1_C04_E04_025_S01.png" width="80%"/> <br/><a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> A and B be the positions of the aircraft for which ` <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> ACB=30^(@)` <br/> Time <a href="https://interviewquestions.tuteehub.com/tag/taken-659096" style="font-weight:bold;" target="_blank" title="Click to know more about TAKEN">TAKEN</a> by the aircraft to go from A to B =10 s <br/> Here OC =3400 m <br/> `tan 15^(@)=(<a href="https://interviewquestions.tuteehub.com/tag/oa-582846" style="font-weight:bold;" target="_blank" title="Click to know more about OA">OA</a>)/(OC)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> OA=OC tan 15^(@)` <br/> `=3400xx0.267=907.8m` <br/>Speed of aircraft` =("Distance "AB)/("Time")` <br/> `=(2xxOA)/(10 s)=(2xx907.8)/(10)` <br/> `=181.56`m</body></html> | |