InterviewSolution
Saved Bookmarks
| 1. |
An aircraft of wing span of 50 m flies horizontally in earth’s magnetic field of 6 × 10-5 T at a speed of 400 m/s. Calculate the emf generated between the tips of the wings of the aircraft. |
|
Answer» Data : l = 50 m, B = 6 × 10-5 T, v = 400 m/s The magnitude of the induced emf, |e| = Blv = (6 × 10-5)(400)(50) = 1.2V |
|