1.

An alcohol on treatment with alkaline KMnO_(4) gives brown ppt. The alcohol is

Answer»

`(C_(2)H_(5))_(3)COH`
`(CH_(3))_(2)C(OH)CH_(3)`
`(CH_(3))_(2)C(OH)CH_(2)CH_(3)`
`(CH_(3))_(2)CHCH_(2)OH`

Solution :`3^(@)`-alcohol cannot be oxidised by ALK. `KMnO_(4)`. During oxidation alk. `KMnO_(4)` forms a brown ppt. of `MnO_(2)`. Here, ALCOHOLS (A), (B) and (C) are `3^(@)` alcohols and as such can't be oxidised by alk. `KMnO_(4)`.


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