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An algebra textbook has a total of 1382 pages. It is broken up into two parts. The secondpart of the book has 64 pages more than the first part. How many pages are in each part ofthe book? |
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Answer» Let number of pages in 1st part is x and number of pages in 2nd part is y. because total number of pages in algebra textbook is 1382 .so, x + y = 1382.......(1) a/c to question, second part of the book has 64 pages more than 1st part .e.g., y = 64 + x .........(ii) put equation (ii) in equation (i), => x + 64 + x = 1382 => 2x + 64 = 1382 => 2x = 1382 - 64 = 1318 => x = 659 put x = 659 in equation (ii), y = 64 + 659 = 723. hence, number of pages in 1st part is 659number of pages in 2nd part is 723 Let the total no. of pages in 1st part be x then, According to the question no. of pages in 2nd part =64+xnow, Total no. of pages book has = 1382x + x + 64 = 13822x = 1318x = 659hence 1st part of book has x= 659 pagesAnd 2nd part has x + 64 = 659 + 64=723 pages********Accept As Best 👍💯****** |
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