An alkane C_(8)H_(18) is obtained as the only product on subjectiog a primary alkyl halide to wurtz reaction. On monobromination this alkane yieles a single isomer of a tertiary bromide . Write the structure of alkane and the tertiary bromide.

An alkane C_(8)H_(18) is obtained as the only product on subjectiog a

1.	An alkane C_(8)H_(18) is obtained as the only product on subjectiog a primary alkyl halide to wurtz reaction. On monobromination this alkane yieles a single isomer of a tertiary bromide . Write the structure of alkane and the tertiary bromide.
Answer» Solution :From wurtz reaction of an alkyl halide gives an alkane with double the number of carbon ATOMS present in the alkyl halide . Here m Wurlz reaction of a primary alkyl halibe gives an alkane `(C_(8)H_(18))` therefore, the alkyl halide must contain four carbon atoms . Now the two possible primary alkyl halides having four corbon atoms each are I and II. (I) `CH_(3)CH_(2)CH_(2)CH_(2)-X` (II) `CH_(3)overset(CH_(3))overset(\|)(CH)-CH_(2)X` Since, alkane `C_(8)H_(18)` on monobromination yields a single isomer of TERTIARY alkyl halide, therefore, the alkane must contain teriary hydrogen. This is possible only if primary alkyl halide (which UNDERGOES wurtz reaction) has a tertiary hydroen.