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An alkyl halide with molecular formula C_(6)H_(13)Br on dehydrohalogenation gave two isomeric alkens X and Y with molecular formula C_(6)H_(12) on reductive ozonolysis X and Y gave fourcompounds CH_(3)COCH_(3)CH_(3)CHOCH_(3)CH_(2)CHO and (CH_(3))_(2) CHCHO find the alkyl halide |
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Answer» Solution :`(i) C_(6) H_(13) Br ` is 3- Bromo -methylpentane. `CH_(3)-underset(CH_(3))underset(|)(CH ) - underset(H)underset(|) overset(Br) overset(|)(C ) -CH_(3)` (ii)3- Bromo-4methyl pentaneon dehydrogenation givetwoisomersx and yas FOLLOWS `CH_(3)- underset(CH)(underset(|)overset( Br)overset(|)(C )- CH_(3) -CH_(3)`  Therefore `C_6H_(13) Br`is 3 Bromo-4-methylpentane |
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