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An alkylhalide with molecular formula C_(6)H_(13)Bron dehydro halogenation gave two isomeric alkenes Xand Y with molecular formula C_(6)H_(12) .On reductive ozonolysis , Xand Y gave four compounds CH_(3)COCH_(3), CH_(3)CHO, CH_(3)CH_(2)CHO and (CH_(3))_(2)CHCHO.Find the alkylhalide. |
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Answer» Solution :`(i)` The alkyl halide with MOLECULAR FORMULA `C_(6)H_(13)BR` is bromohexane (`2`-"Bromo"`-2,3`-"dimethylbutane") `(ii)` `C_(6)H_(13)Br` on dehydro halogenation gives two isomeric alkenes `2`,`3`- dimethyl-`1`-BUTENE `(X)` and `2`,`3`-dimethyl-`2`-butene`(Y)` `H_(3)C-underset(CH_(3))underset(|)(C )H-overset(Br)overset(|)underset(CH_(3))underset(|)(C )-CH_(3) overset(."alc"KOH)(to)`  `(iii) X` and `Y` on reductive ozonolysis GAVE four compounds `CH_(3)COCH_(3)`, `CH_(3)CHO`, `CH_(3)CH_(2)CHO` and `(CH_(3))_(2)CHCHO`, `(iv)` `X-2,3` dimethyl -`1`-butene `Y-2,3` dimethyl -`2`-butene |
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