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An alpha nucleus of energy `(1)/(2)m nu^(2)` bombards a heavy nucleus of charge `Ze` . Then the distance of closed approach for the alpha nucleus will be proportional toA. 1/mB. `1//v^(2)`C. 1/zeD. `v^(2)` |
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Answer» Correct Answer - A Distamnce of closet apporach , ` r_(0)=(Ze^(2))/(2mv^(2)piepsi_(0))` ` rArr " " r_(0)prop (1)/(m)` |
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