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InterviewSolution
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An `alpha`- particle accelerated through V volt is fired towards a nucleus. It distance of closest approach is r. If a proton accelerated through the same potential is fired towards the same nucleus, the distance of closest approach of the proton will be :A. rB. 2rC. `(r)/(2)`D. `(r)/(4)` |
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Answer» Correct Answer - A Decreases in kinetic energy = increases in potential energy `:. " " qV=(1)/(4piepsi_(0))*(Q*q)/(r)` `:. " " r=(Q)/((4piepsi_(0))V)` |
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