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An `alpha` - particle and a proton are accelerated through same potential difference. Find the ratio `(v_(a)//v_(p))` of velocities acquired by two particles. |
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Answer» Gain in KE of particle = Qv `(1)/(2)"m"_(p)"v"_(p)^(2) = K_(p) = q_(p)V_(p) .............(i)V_(p) = Vprop = V` `(1)/(2)"m"_(prop)"v"_(prop)^(2) = K_(prop) = q_(prop)V_(prop) .............(i)` (ii)/(i) `(m_(prop)v_(prop)^(2))/(m_(p)v_(p)^(2)) = (q_(prop))/(q_(p)) = (2)/(1)` `(v_(prop)^(z))/(v_(p)^(2)) = (m_(p) xx 2)/(m_(alpha) xx 1) = (Zm_(p))/(4m_(p) xx 1) = (1)/(2)` `V_(prop) : V_(p) = 1 : sqrt(2)` |
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