An alpha particle was projected with 5.4 mev energy toward nucleus of – InterviewSolution

InterviewSolution

1.

An alpha particle was projected with 5.4 mev energy toward nucleus of cu z(29) what is the closest distance of approach.

Answer»

9.6×10−15m

Solution :

Here, E=8.7MeV=8.7×1.6×10−13J

Z=29,R0=?

r0=2Ze24π∈0(E)

=9×109×2×29(1.6×10−19)28.7×1.6×10−13

r0=9.6×10−15m

Discussion

No Comment Found

Related InterviewSolutions

How have the people of the Community helped one another ? What role do the women of Kalikuda play during these daysClass-9th, Moment book, NCERT, CBSE, ‘Weathering The Strom In Ersana’
Write the electronic configuration for Chlorine atom shown belowneed answer
Write the electronic configuration for the atom shown below.
How many electrons are there in the Valence shell of the structure shown below?urgent!!!!!!!!!!!!!!!!!!!!!nowwwwwwwww
One property of Halogen is its Density increases down the group. Give other two physical Properties of Halogen.plz get to the point
Write the relationship between number of moles (n) and atomic mass (n)
In two or more complete sentences explain how to balance the chemical equation,Ca + N2 ⟶ Ca3 + N2 and include all steps.
What is the difference between rate of percolation and water retained
Can anyone help me?this question is from chemistry subject 9th class (Sri Chaitanya)school CBSE board syllabustopic chemical kinetics don't give worest answers okk I will report
practical on conservation of Mass of chemical reaction between copper sulphate and sodium sulphide in aqueous solution