1.

An alternating e.m.f. given by e=200 sin 50 t is applied to a circuit containing only a resistance of `50 Omega`. What is the value of r.m.s. current in the circuit?A. 2.828 AB. 28.28 AC. 0.2828 AD. 0.02828 A

Answer» Correct Answer - A
`I_(0) = (e_0)/(R) = 200/50 = 4A`
`:. I_(rms) = (I_0)/(sqrt2) = 4/(sqrt2) = 2sqrt(2) = 2 xx 1.414 = 2.828 A`.


Discussion

No Comment Found

Related InterviewSolutions