An alternating voltage given by `E = 280 sin 50 pi t` is connected across a pure resistor of 40 ohm. Find frequency of source and rms current through the bulb.

An alternating voltage given by `E = 280 sin 50 pi t` is connected acr

1.	An alternating voltage given by `E = 280 sin 50 pi t` is connected across a pure resistor of 40 ohm. Find frequency of source and rms current through the bulb.
Answer» (i) `V_(0)=280 V,` `omega = 50 pi rArr 2pi v = 50 pi rArr v=25 Hz` (ii) `I_(rms)=(V_(rms))/(R)=(V_(0)//sqrt(2))/(R)=(280)/(sqrt(2)xx40)=3.5xx1.414=4.95 A.`

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An alternating voltage given by `E = 280 sin 50 pi t` is connected across a pure resistor of 40 ohm. Find frequency of source and rms current through the bulb.

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