InterviewSolution
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InterviewSolution
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An alternating voltage is given by `E = 100 sin( omega +(pi)/(6))V`. The voltage will be maximum for the first time when is [T = periodic time)A. `(T)/(12)`B. `(T)/(2)`C. `(T)/(6)`D. `(T)/(3)` |
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Answer» Correct Answer - C Given , alternating voltage is ` E = 100 sin ( omega t + ( pi ) /( 6 ) ) V ` ltBrgt The voltage will maximum, when `sin ( omega t + ( pi ) / ( 6 ) ) = 1 ` ` rArr sin ( omega t+ ( pi ) / ( 6 ) ) = sin"" (pi ) /(6) ` ` rArr omega t+ ( pi ) / ( 6 ) = ( pi ) / ( 2 ) ` ` rArr omega t = ( pi ) / ( 3 ) ` ` rArr t = ( pi ) /( 3 omega ) = ( pi xx T ) /( 3 xx 2pi ) " " [ because omega = ( 2 pi ) /( T) ] ` ` = ( T ) /( 6 ) ` Thus, the voltage will be maximum for the first time when ` t = ( T ) / ( 6 ) `. |
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