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An alternating voltage is represented by =254.56377 . 1.2.1 calculate the time taken from =0seconds for the for the voltage to reach a value of 180V for the second time. (6) 1.2.2 Calculate the energy dissipated when the voltage is connected across a 9.6Ω resistor for half an hour. (3) 1.2.3 Calculate the current flowing through the resistor in the form of =sin(∓) (3) |
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Answer» So the calculation part starts,Length=1 km=1000mRadius=1 mm=1*10⁻³ mResistivity of copper=1.72x10⁻⁸Resistance=(Resistivity of copper * Length)/(Area) =(Resistivity of copper * Length)/(r²)Resistance=[1.72*10⁻⁸*1000]/[22/7*(1*10⁻³)²Resistance=5.5 OHM Read more on Brainly.in - brainly.in/question/394636#readmoreExplanation:length=1 km= 1000 mradius=1 mm= 10^(-3)cross sectional area=pi*R^2=3.14*10^(-6)Resistivity=1.72x10^(-8)so,R=(1.72x10^(-8))(10^3)/(3.14x10^(-6)R=1.72x10/3.14=1720/314=5.478 ohmsPLZ MARK IT AS BRAINLIEST..Read more on Brainly.in - brainly.in/question/394636#readmore |
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