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An alternating voltage v(t) = 220 sin 100wt voltis applied to a purely resistive load of 50 ohm. Thetime taken for the current to rise from half ofthe peak value to the peak value is(1) 2.2 ms (2) 7.2 ms(3) 5 ms (4) 3.3 ms |
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Answer» An alternating voltage v(t) = 220 sin 100wt volt is applied to a purely resistive load of 50 ohm. The time taken for the current to rise from half of the peak value to the peak value is (1) 2.2 ms (2) 7.2 ms (3) 5 ms (4) 3.3 ms |
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