An aluminum wire of length 60 cm is joined to a steel wire of length 80 cm and stretched between two fixed supports. The tension produced is 40 N. Cross-sectional area is 1 mm2 (steel) and 3 mm2 (aluminum). Minimum frequency of the tuning fork which can produce standing waves with the joint as a node is nearly equal to (density of Al=2.6 g cc−1 and density of steel =7.8 g cc−1)

An aluminum wire of length 60 cm is joined to a steel wire of length 8

1.	An aluminum wire of length 60 cm is joined to a steel wire of length 80 cm and stretched between two fixed supports. The tension produced is 40 N. Cross-sectional area is 1 mm2 (steel) and 3 mm2 (aluminum). Minimum frequency of the tuning fork which can produce standing waves with the joint as a node is nearly equal to (density of Al=2.6 g cc−1 and density of steel =7.8 g cc−1)
Answer» An aluminum wire of length $60 cm$ is joined to a steel wire of length $80 cm$ and stretched between two fixed supports. The tension produced is $40 N$ . Cross-sectional area is $1 {mm}^{2}$ (steel) and $3 {mm}^{2}$ (aluminum). Minimum frequency of the tuning fork which can produce standing waves with the joint as a node is nearly equal to (density of $A l = 2.6 {g cc}^{- 1}$ and density of steel $= 7.8 {g cc}^{- 1})$

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