1.

An AM wave has `1800` watt of total power content, For `100%` modulation the carrier should have power content equal toA. `1000` wattB. `1200` wattC. `1500` wattD. `1600` watt

Answer» Correct Answer - b
`P_(t)=P_(c)(1+(m_(a)^(2))/(2))`, Here `m_(a)=1`
`implies 1800=P_(c)(1+((1)^(2))/(2))impliesP_(c)=1200W`


Discussion

No Comment Found

Related InterviewSolutions