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An `AM` wave is given by `V=1500[1+0.5sin12560t]sin(5.26xx10^(5)t)`. The modulating frequency isA. `2.0 kHz`B. `1.0 kHz`C. `12.5 kHz`D. `50 kHz` |
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Answer» Correct Answer - A `C_(m)(t)=A_(c)(1+musin omega_(m)t)sin omega_(c)t` `f_(m)=(omega_(m))/(2pi)=(12560)/(2pi)=2khz` |
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