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An ammeter has resistance `R_(0)` and range l what resistance should be connected in parallel with it to increase its range by nl ?A. a series resistance of `(G)/(n +1) Omega`B. a shut of `(G)/(n +1) Omega`C. a shut of `(G)/(n +1) Omega`D. a series resistance of `(G)/(n -1) Omega` |
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Answer» Correct Answer - B The range of an ammeter can be increased by connecting a shunt or parallel resistance to it, whose value is given by `R = ((l_(g))/(l-l_(g))) G Omega` To increase the range from l to nl, the current passing through it is l` = nl_(g)`, Using this value in Eq. (i), we get `R = ((l_(g))/(nl-l_(g))) G Omega` ` =(G)/((n-1)) Omega` |
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