1.

An amount increased by 36% in 3 year invested on simple interest, what will be the compound interest earned on 10000 in 2 years at same rate?1). 23002). 25003). 25444). 2100

Answer»

LET Principal be Rs X. So after 3 years amount would be = 136x/100

∴ SI = Amount – Principal = 136x/100 – x = 36x/100

⇒ SI = (P × R × t) /100

⇒ 36x/100 = (x × r × 3) /100

⇒ r = 12%

$(A = 10000{\left( {1 + \frac{{12}}{{100}}} \right)^2})$

⇒ A = 12544

⇒ Compound Interest = 12, 544 – 10, 000 = 2544


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