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An amount increased by 36% in 3 year invested on simple interest, what will be the compound interest earned on 10000 in 2 years at same rate?1). 23002). 25003). 25444). 2100 |
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Answer» LET Principal be Rs X. So after 3 years amount would be = 136x/100 ∴ SI = Amount – Principal = 136x/100 – x = 36x/100 ⇒ SI = (P × R × t) /100 ⇒ 36x/100 = (x × r × 3) /100 ⇒ r = 12% $(A = 10000{\left( {1 + \frac{{12}}{{100}}} \right)^2})$ ⇒ A = 12544 ⇒ Compound Interest = 12, 544 – 10, 000 = 2544 |
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