An amount of heat passing through a metallic rod in time t is given byQ=(KA(T_(1)-T_(2))t)/(I) where k= thermal conductivity A= Cross sectional area, T_(1) and T_(2) are temeprature of hot and cold ends respectively and L= length. So the dimesional formula for k=.....

An amount of heat passing through a metallic rod in time t is given by

1.	An amount of heat passing through a metallic rod in time t is given byQ=(KA(T_(1)-T_(2))t)/(I) where k= thermal conductivity A= Cross sectional area, T_(1) and T_(2) are temeprature of hot and cold ends respectively and L= length. So the dimesional formula for k=.....
Answer» Solution :`Q=(KA(T_(1)-T_(2))t)/(L)` is given `:.k=(QL)/(A(T_(1)-T_(2))t)....(i)` Where, HEAT energy `[Q]=M^(1)L^(2)T^(-2)` Length `[L]=L^(1)` area `[A]=L^(2)` differerence of temperature. `(T_(1)-T_(2))=[DeltaT]=K^(1)` time `[t]=T^(1)` Note that here we have included K (for temperature) along with M, L and T. Substituting these dimensional FORMULA in equation (1), we GET `[k]=(M^(1)L^(2)T^(-2)L^(1))/(L^(2)L^(1)T^(1)=M^(1)L^(1)T^(-3)K^(-1)`