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An angular magnification of 30X is desired using an objective of focal length 1.25 cm and an eye piece of focal length 5 cm. How will you set up the compound microscope for the final image formed at least distance of distinct vision? |
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Answer» me = 1 + 25/5 = 6 mo = 30 / me = 5 mo = vo / -uovo = - 5 uo 1/fo = 1/vo – 1/uofo = - (5/6) uo uo = 1.5 cm , vo = 7.5 cm ue = - 4.17 cm Length of the tube = ue + vo = 11.67 cm |
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