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An aqueous solution containing 1 mol of `HgI_(2)` and `2mol` of Nal is orange in colour. On addition of excess NaI the solution becomes colourless The orange colour reappears on subsequent addition of Na `OCI` Explain with equations . |
Answer» `HI_(2)` has orange/scarlet colour It issolves in sodium iodide due to the formation of complex `HgI_(2) + 2NaI rarr Na_(2) HgI_(4)` With `NaOCI` again a precipitate of `HgI_(2)` is formed `3Na_(2)HgI_(4) +2NaOCI+2H_(2)O` `rarr 3HgI_(2) +2NAI_(3) + 4NaOH + 2NaCI` . |
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