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An aqueous solution that is `3.5%` sodium chloride by mass can be prepared by dissolving `3.5g` of `NaCl` in `.........g` of `H_(2) O`A. `100`B. `103.5`C. `96.5`D. less than `100` |
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Answer» Correct Answer - C `3.5% NaCl` by mass contains `3.5g NaCl` in `100.0g` of solution. Thus, Mass of `H_(2) O` = (Mass of solution) - (mass of solute) `= (100.0 - 3.5)g = 96.5g` |
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