An array A[50][30] is stored along the row in the memory with each ele

1.	An array A[50][30] is stored along the row in the memory with each element requiring 4 bytes of storage. If the element A[10][15] is stored at 21500, then find out the base address of the array and the memory address of element stored at location A[30][25]?
Answer» Row-major Formula:- A[I][J]= B+ W((I-Lr)Nc + (J-Lc)) Nr=50, Nc=30, B=?, W=4, Lr=0, Lc=0, A(10,15)=21500 A[10][15]= B + 4((10-0)30 + (15-0)) 21500= B + 4(300+15) 21500=B + 4315 B=21500 – 1260 B=20240 A[30][25] = 20240 + 4((30-0)30 + (25-0)) A[30][25] = 20240 + 4(900+25) A[30][25] = 20240 + 4925 A[30][25] = 23940

An array A[50][30] is stored along the row in the memory with each element requiring 4 bytes of storage. If the element A[10][15] is stored at 21500, then find out the base address of the array and the memory address of element stored at location A[30][25]?

Answer»

Row-major Formula:- A[I][J]= B+ W*((I-Lr)*Nc + (J-Lc))

Nr=50, Nc=30, B=?, W=4, Lr=0, Lc=0, A(10,15)=21500

A[10][15]= B + 4*((10-0)*30 + (15-0))

21500= B + 4*(300+15)

21500=B + 4*315

B=21500 – 1260

B=20240

A[30][25] = 20240 + 4*((30-0)*30 + (25-0))

A[30][25] = 20240 + 4*(900+25)

A[30][25] = 20240 + 4*925

A[30][25] = 23940

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An array A[50][30] is stored along the row in the memory with each element requiring 4 bytes of storage. If the element A[10][15] is stored at 21500, then find out the base address of the array and the memory address of element stored at location A[30][25]?

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