An array P[30][20] is stored along the column in the memory with each

1.	An array P[30][20] is stored along the column in the memory with each element requiring 2 bytes of storage. If the base address of the array P is 26500, find out the location of P[20][10].
Answer» Total number of rows= 30 Total size= 2 bytes Base Address= 26500 LOC (P[I][J]) = BaseAddress+((I-LBR) + (J-LBC) * R)W Assuming Lower Bound of Row(LBR)=0 Lower Bound of Column(LBC)=0 Total number of Rows(R)=30 Size of each element(W)=2 LOC(P[20][10])= 26500 +((20-0)+(10-0)30)*2 LOC(P[20][10])= 26500 +640 LOC(P[20][10])= 27140

An array P[30][20] is stored along the column in the memory with each element requiring 2 bytes of storage. If the base address of the array P is 26500, find out the location of P[20][10].

Answer»

Total number of rows= 30

Total size= 2 bytes

Base Address= 26500

LOC (P[I][J]) = BaseAddress+((I-LBR) + (J-LBC) * R)*W

Assuming Lower Bound of Row(LBR)=0

Lower Bound of Column(LBC)=0

Total number of Rows(R)=30

Size of each element(W)=2

LOC(P[20][10])= 26500 +((20-0)+(10-0)*30)*2

LOC(P[20][10])= 26500 +640

LOC(P[20][10])= 27140

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An array P[30][20] is stored along the column in the memory with each element requiring 2 bytes of storage. If the base address of the array P is 26500, find out the location of P[20][10].

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