An array S[10] [30] is stored in the memory along the column with each

1.	An array S[10] [30] is stored in the memory along the column with each of its element occupying 2 bytes. Find out the memory location of S[5][10], if element S[2][15] is stored at the location 8200.
Answer» OPTION 1: ASSUMING LBR=LBC=0 W=2 BYTES, NUMBER OF ROWS(M)=10, NUMBER OF COLUMNS(N)=30 LOC(S[I][J]) = B +(I + JM)W LOC(S[2][15]) = B +(2+1510) 2 8200 = B + (1522) B = 8200 - 304 B = 7896 LOC(S[5][10]) = 7896 +(5+1010)* 2 = 7896 + (1052) = 7896 + 210 = 8106 OPTION 2:* ASSUMING LBR=2,LBC=15 AND B = 8200 W=2 BYTES, NUMBER OF ROWS(M)=10, NUMBER OF COLUMNS(N)=30 LOC(S[I][J]) = B +((I-LBR) + (J-LBC)M)W LOC(S[5][10])= 8200 + ((5-2) + (10-15)10)2 = 8200 + (3 + (-5)10) 2 = 8200 + (3 + (-50)) * 2 = 8200 + (3 – 50) * 2 = 8200 + (-47) * 2 = 8200 – 94 = 8106

An array S[10] [30] is stored in the memory along the column with each of its element occupying 2 bytes. Find out the memory location of S[5][10], if element S[2][15] is stored at the location 8200.

Answer»

OPTION 1:

ASSUMING LBR=LBC=0

W=2 BYTES, NUMBER OF ROWS(M)=10, NUMBER OF COLUMNS(N)=30

LOC(S[I][J]) = B +(I + J*M)*W

LOC(S[2][15]) = B +(2+15*10)* 2

8200 = B + (152*2)

B = 8200 - 304

B = 7896

LOC(S[5][10]) = 7896 +(5+10*10)* 2

= 7896 + (105*2)

= 7896 + 210

= 8106

OPTION 2:

ASSUMING LBR=2,LBC=15 AND B = 8200

W=2 BYTES, NUMBER OF ROWS(M)=10, NUMBER OF COLUMNS(N)=30

LOC(S[I][J]) = B +((I-LBR) + (J-LBC)*M)*W

LOC(S[5][10])= 8200 + ((5-2) + (10-15)*10)*2

= 8200 + (3 + (-5)*10) * 2

= 8200 + (3 + (-50)) * 2

= 8200 + (3 – 50) * 2

= 8200 + (-47) * 2

= 8200 – 94

= 8106

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