1.

An article is marked up 40% higher than CP but it was sold x% on discount. The shopkeeper thus gains 12%. What would be the S.P. of the article with C.P. ₹ 120 and sold on x % profit

Answer»

₹132.50
₹144
₹128
₹148

Solution :Let C.P = 100
`therefore` M. P = 140
And `S.P = (100 -X)/(100) XX 140`
Also, `S.P = (112)/(100) xx 100 = 112`
`therefore (100-x)/(100) xx 140 =112`
`rArr x = 20`
Now, C.P = 120 PROFIT = x%, i.e., 20%
`therefore S.P = (120)/(100) xx 120 = ₹144`


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