An artificial satellite is revolving in a circular orbit at a height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km, mass is 6 xx 10^(24) kg find the orbital velocity (G = 6.67 xx 10^(-11)Nm^(2)//kg^(2))

An artificial satellite is revolving in a circular orbit at a height o

1.	An artificial satellite is revolving in a circular orbit at a height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km, mass is 6 xx 10^(24) kg find the orbital velocity (G = 6.67 xx 10^(-11)Nm^(2)//kg^(2))
Answer» Solution :`V_(0) = sqrt((GM)/(R+H)) = sqrt(((6.67 XX 10^(-11))(6 xx 10^(24)))/((6400 xx 10^(3)) + (1200 xx 10^(3))))` `= sqrt((6.68 xx 10^(-11) xx 6 xx 10^(24))/(7600 xx 10^(3))) = 7.26 km//s`