An artificial satellite is revolving in a circular orbit at a height of 1200km above the surface of the earth. If the radius of the earth is 6400km, mass is 6xx10^(24) find the orbital velocity (G=6.67xx10^(-11)Nm^(2)//kg^(2))

An artificial satellite is revolving in a circular orbit at a height o

1.	An artificial satellite is revolving in a circular orbit at a height of 1200km above the surface of the earth. If the radius of the earth is 6400km, mass is 6xx10^(24) find the orbital velocity (G=6.67xx10^(-11)Nm^(2)//kg^(2))
Answer» Solution :`V_(0)SQRT((GM)/(R+h))=sqrt(((6.67xx10^(-11))(6XX10^(24)))/((6400xx10^(3))+(1200xx10^(3))))` `=sqrt((6.67xx10^(-11)xx6xx10^(24))/(7600xx10^3))=7.26km//s`