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An artificial satellite is revolving in a circular orbit at a height of 1200km above the surface of the earth. If the radius of the earth is 6400km, mass is 6xx10^24 kg find the orbital velocity (G=6.67xx10^(-11) Nm^2//kg^2) |
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Answer» SOLUTION :`V_0=SQRT((GM)/(R+h))=sqrt(((6.67xx10^(-11))(6xx10^24))/((6400xx10^3)+(1200xx10^3)))` `=sqrt((6.67xx10^(-11)xx6xx10^24)/(7600xx10^3))`=7.26 km/s |
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