InterviewSolution
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InterviewSolution
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An astronomical telescope arranged for normal adjustment has a magnification of 6. If the length of the telescope is 35cm, then the focal lengths of objective and euye piece respectivley =, areA. 30cm,5cmB. 5cm,30cmC. 40cm,5cmD. 30cm,6cm |
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Answer» Correct Answer - A In normal adjustment,the object and the final image both are at infinity and the separation between the objective and the eye pieces si `f_(u)+f_(e)` Thus , `f_(u)+f_(e)=35cm…..(i)` Also, the magnifying power of the telescope in normal adjustment is `m=-(f_(u))/(f_(e))=-6 ("give")` `f_(u)=6f_(e) .....(ii)` On solving Eqs. (i) and (ii) we get `f_(v)=30cm and f_(e)=5cm` |
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