An athlete has taken 100 g glucose of energy equivalent to 1560 kJ. He utilizes 50% of this gained energy in an event. In order to avoid storage of energy in the body, calculate the mass of water he would need to perspire.(Enthalpy of H2O for evaporation = 44 kJ mol 1)(A). 346 g(B). 316 g(C) 323 g(D). 3199

An athlete has taken 100 g glucose of energy equivalent to 1560 kJ. He

1.	An athlete has taken 100 g glucose of energy equivalent to 1560 kJ. He utilizes 50% of this gained energy in an event. In order to avoid storage of energy in the body, calculate the mass of water he would need to perspire.(Enthalpy of H2O for evaporation = 44 kJ mol 1)(A). 346 g(B). 316 g(C) 323 g(D). 3199
Answer» B . 316 gm Explanation:UPON utilizing 50% energy , energy to be stored = 780 kJ enthalpy of H20 vaporization = 44 kJ /mol No of MOLES of vaporized water = 780 / 44 = 17.7 molMass of 1 mol of water = 18 G mass of 17.7 mol water = 17.7 × 18 = 316 g (APPROXIMATELY)..please mark this answer if it was helpful.